Hi guys good night please help me in this.............
In a code mango is termed as obngo and score is termed as pdtre, then how start will be coded as.
Proper explanation is required.
Answers
Answer:
Start will be coded as WUKAT
Step-by-step explanation:
Writing the alphabets in the sequential number-wise:
A(1), b(2), C(3),d(4), e(5), f(6), g(7), h(8),i(9),j(10),k(11), l(12), m(13), n(14), o(15), p(16), q(17), r(18), s(19), t(20), u(21), v(22), w(23), x(24), y(25), z(26)
M(13) A(1) N(14) G(7) O(15)
O(15) B(2) N(14) G(7) O(15)
S(19) C(3) O(15) R(18) E(5)
P(16) D(4) T(20) R(18) E(5)
Since, each time in the coding letters are getting increased by one, in the first case only first two letters got changed, in the second case first three letters got changed so, in the next schedule it might be get changed by 4.
It is a series following for the first letter is increasing by which number difference next time is decreasing by adding 1 with the difference, so, next time it will get increased by 1 from the difference of decreasing
In first case,
m(13) = o(15) (increase by 2)
Here, the numerical factor o belongs to the 15th and the second greatest factor of 15 is 5.
In the second case,
s(19) = p(16) (decrease by 3)
So, in the third case, it might be,
s(19) = w(23) (increase by 4)
So, instead of 's' we are getting 'w'
For the second number its only getting increased by 1
in 1st case:
a(1) = b(2) (increasing by 1)
in 2nd case:
c(3) = d(4) (increasing by 1)
So, in the 3rd case,it might be,
t(20) = u=(21) (increasing by 1)
So, instead of 't' we are getting 'u'
For the third case, it is getting increased by a sum of 5 and it is increasing series wise, 0 to, 5 in the first and second series so, it might be increased by 10 in the third series.
In 1st case:
n(14) = n(14) (increasing by 0)
in 2nd case:
O(15) = t(20) (increasing by 5)
In the third case as per the series it will might be increased by 10.
a(1) = k(11)
So, instead of 'a' we are getting 'k' here.
As per the series for the first case it got changed upto 2 letters in the second case by 3 letters so, it can be said that for each case coding the number of interchanged letters are getting increased by 1, so, it might be upto 4 letters in case 3.
If we follow the series, then newly changed number is interchanging by an addition of it term which belongs to its numerical sum with its second greatest factor.
in case 1 there is no change
in the second case fir the last interchanged letter:
O(15) = t(20) (increasing by 5)
Here, the numerical factor o belongs to the 15th and the second greatest factor of 15 is 5.
So, for the third case, we should change 'r', which belongs to 18.
And the second greatest factor of r is 9.
But, if we add 18 and 9 then then we get, 27
But there are 26 letters, so, it will revolve around and it will be the term which is equal to the division of the result by 26.
So, by dividing 27 by 26 we get the remainder as 1.
And the first term is 'a'.
So, instead of 'r' we are getting 'a' here.
And the last letter, that is, 't' will remain unchanged.
So, the code for 'START' is 'WUKAT'.
Follow: https://brainly.in/question/13633888 for the similar content.
Step-by-step explanation:
As per the series for the first case it got changed upto 2 letters in the second case by 3 letters so, it can be said that for each case coding the number of interchanged letters are getting increased by 1, so, it might be upto 4 letters in case 3.
If we follow the series, then newly changed number is interchanging by an addition of it term which belongs to its numerical sum with its second greatest factor.
But there are 26 letters, so, it will revolve around and it will be the term which is equal to the division of the result by 26.
Here, the numerical factor o belongs to the 15th and the second greatest factor of 15 is 5.
But, if we add 18 and 9 then then we get, 27
So, for the third case, we should change 'r', which belongs to 18.
in the second case fir the last interchanged letter