hi guys help me answer this two questions plzzzz
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hello frnd!!
here's ur answer...
1.given:-
base=18cm
height=12cm
therefore area=b×h
=18×12
=216cm²
2.
let the diagnols of the rhombus be 4x and 3x.
area of the rhombus=384cm²
1/2×d1×d2=384cm²
1/2×4x×3x=384cm²
1/2×12x²=384cm²
12x²=384/1×2/1
12x²=768
x²=768/12
x²=64
x=√64
x=8cm
hence, length of the 1st diagonal=4x
=8×4
=32cm
2nd diagonal=3x
=3×8
=24cm
hope this helps...
☺☺☺
here's ur answer...
1.given:-
base=18cm
height=12cm
therefore area=b×h
=18×12
=216cm²
2.
let the diagnols of the rhombus be 4x and 3x.
area of the rhombus=384cm²
1/2×d1×d2=384cm²
1/2×4x×3x=384cm²
1/2×12x²=384cm²
12x²=384/1×2/1
12x²=768
x²=768/12
x²=64
x=√64
x=8cm
hence, length of the 1st diagonal=4x
=8×4
=32cm
2nd diagonal=3x
=3×8
=24cm
hope this helps...
☺☺☺
uhana:
ki
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