Question

hi guys I am challenging the brilliant members on brainly to solve this great question

A train of mass 10 tonnes is moving at 9km/hr and after 20 seconds it is moving at 45km/hr.what is the average force acting upon it during this time in the direction of motion?

Answer 1

HEY BUDDY..!!!

HERE'S THE ANSWER..

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♠️ It is clear that train has accelerated in 20 seconds from 9 km / h to 45 km / h , We'll first find the Acceleration

⏺️ we know

✔️ Acceleration = ( final velocity - initial velocity ) / time

♠️ Before applying formula , here are some conversions

⏺️ 10 tonnes = 10,000 kg

⏺️ 9 km / h = 2.5 m / s

⏺️45 km / h = 12.5 m / s

▶️ Now finding Acceleration

=> Acceleration = ( final velocity - initial velocity ) / time

=> Acceleration = ( 12.5 - 2.5 ) / 20

=> Acceleration = 10 / 20

=> Acceleration ( a ) = 0.5 m / s^2

♠️ Now we know force is product of mass ( m ) and Acceleration ( a ), i.e

✔️ F = m × a

=> F = 10,000 × 0.5

=> [ F = 5000 N or 5000 Kg m / s^2 ]✔️✔️


HOPE HELPED..

JAI HIND..

:-)

Answer 2

a = v-u / t

a=0.5

F = m . a

F= 10000×0.5

F = 5000N


F = 5000 N