Question

hi guys I have mathematics doubt​

Answer 1

Answer:

$2y^2-5y-18 =$$\left(y+2\right)\left(2y-9\right)$

Step-by-step explanation:

  $2y^2-5y-18$

$=\left2y^2+4y-9y-18\right$

$=2y\left(y+2\right)-9\left(y+2\right)$

$=\left(y+2\right)\left(2y-9\right)$

Answer 2

Answer:

2y² _ 5y _ 18

2y² _ 9y + 4y _ 18

y(2y_ 9) + 2(2y _ 9)

(y +2 ) (2y _ 9)

y+ 2 =0

y = –2

also, 2y _ 9= 0

y= 9/2