Question

Hi guys....I need help....pls explain the ans. With steps

Answer 1

Explanation:

we know that

gravitational force directly proportional to product of mass of two bodies inversely proportional to square of the distance between the two bodies.

in case of sphere gravitational force = GMm/R^2 (Where M and m are mass of two bodies and R is the distance between them )

So

GMm/R^2 = F

Mass of solid sphere removed =

$= \frac{m}{ \frac{4}{3} \times \pi {r}^{3} } \times \frac{4}{3} \pi { (\frac{d}{2} )}^{3} = \frac{m}{g}$

since mass of small sphere is very small so take M= 1

F'=

$\frac{g( \frac{m}{8}1 }{ {3r }^{2} } = \frac{gm \times 1}{ {r}^{2} } \times \frac{1}{8} \times \\ = 4f \times \frac{1}{</u></em><em><u>8</u></em><em><u>} = \frac{f}{</u></em><em><u>8</u></em><em><u>}$

So force due to remaining sphere

F" = F - F' = F - F/8 = 7F/8