Chemistry, asked by tesswaver1, 7 months ago

Hi guys. i need some help with some chemistry problems, it's about electrolysis. it would mean a lot to me if anyone one of you guys could solve it and to give explanations for your answers!

4 Copper is purified by electrolysis, as in the example
shown below.

a Name the materials used for the electrodes A and B.
b Name the electrolyte C and substance D.
c Why is substance D of economic importance in
respect of this process?
d Write equations for the reactions which take place
at the cathode and anode during this process.
e Draw a labelled diagram to show the cell after
electrolysis has taken place.
f Why has electrolyte C to be acidified with the
dilute sulfuric acid
g Why does copper have to be 99.99% pure for use
in electrical cables?

Answers

Answered by ratnaaryans
3

Answer:

YOUR ANSWER

Explanation:

Purifying copper by electrolysis

1. A beaker with pure and impure copper rods dipped into copper(II) sulfate solution

During electrolysis, the anode loses mass as copper dissolves, and the cathode gains mass as copper is deposited.

The slideshow shows what happens during the purification of copper by electrolysis:

Two vertical copper rods. Four Cu ions are attached to the rod on the right, and four Cu2+ ions are floating in the space between the rods.

The purification of copper by electrolysis

1. Four Cu ions are attached to the rod on the right, and four Cu²+ ions are floating in the space between the rods

A half-equation shows what happens at one of the electrodes during electrolysis. Electrons are shown as e-.

These are the half-equations:

anode: Cu → Cu2+ + 2e- (oxidation)

cathode: Cu2+ + 2e- → Cu (reduction)

Oxidation happens at the anode because electrons are lost. Reduction happens at the cathode because electrons are gained.

One way to remember this is by using the mnemonic OIL RIG:

Oxidation Is Loss of electrons, Reduction Is Gain of electrons.

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Answered by diponarya
1

Answer:

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