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Answers
Let the speed of the train be x km/hr and the speed of the bus is y km/hr.
So according to question and using :
Total distance =300 km
Roohi travels 60 km by train and 300−60=240 by bus in 4 Hours,
and 100 km by train, 300−100=200 by bus, and takes 10 minutes more.
Now, let
then 60u + 240v = 4.............eq 1
Multiply eq1 by 5 and eq2 by 6 we get
300u+1200v=20..........eq3
600u+1200v=25...........eq4
Subtracting eq3 and eq4 we get
−300u=−5
Putting the value of u in eq1 we get
Now
and
Hence the speed of the train is 60 km/hr and the speed of the bus is 80 km/.
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Answer:
Solution :-
Let the speed of train and bus be u km/h and v km/h.
According to the Question,
60/u + 240/v = 4 ... (i)
100/u + 200/v = 25/6 ... (ii)
Putting 1/u = p and 1/v = q in the equations, we get
⇒ 60p + 240q = 4 ... (iii)
⇒ 100p + 200q = 25/6
⇒ 600p + 1200q = 25 ... (iv)
Multiplying equation (iii) by 10, we get
⇒ 600p + 2400q = 40 .... (v)
Subtracting equation (iv) from (v), we get 1200q = 15
⇒ q = 15/200 = 1/80 ... (vi)
Putting equation (iii), we get
⇒ 60p + 3 = 4
⇒ 60p = 1
⇒ p = 1/60
⇒ p = 1/u = 1/60 and q = 1/v = 1/80
⇒ u = 60 and v = 80
Speed of train = 60 km/h
Speed of bus = 80 km/h.
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