Hi guys please answer this question tomorrow exam pleaseI will read the question once again sorry if it if it’s not leave you can just use this in figure triangle ABC is an equilateral triangle with coordinates of BNCSB1, zero and C5, zero find the coordinate of war taxi please answer guys please
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Answer:
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Step-by-step explanation:
ANSWER
Two vertices of an equilateral triangle are (0,0)and(3,√3).
Let the third vertex of the equilateral triangle be (x,y)
Distance between (0,0)and(x,y) = Distance between(0,0)and(3,√3) = Distance between (x,y)and(3,√3)
(x
2
+y
2
)
=
(3
2
+3)
=
(x−3)
2
+(y−
3
)
2
x
2
+y
2
=12
x
2
+9−6x+y
2
+3−2
3y
=12
24−6x−2
3y
=12
−6x−2
3y
=−12
3x+
3y
=6
x=
3
6−
3y
3
(6−
3y
)
2+y
2
=12
9
(36+3y2−12
3y
)
+y
2
=12
36+3y
2
−12
3y
+9y2=108
−12
3y
+12y
2
−72=0
−3y
+y2−6=0
(y−2
3
)(y+
3
)=0
y=2
3
or
−3
Ify=2
3
,x=(6−6)/3=0
Ify=−
3
,x=
3
9
=3
So,the third vertex of the equilateral triangle=(0,2
3
)or(3,−
3
).
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