Question

Hi guys please help me in solving Q23 and Q24
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Answer 1

Answer:

23) 34

24) (1) Rs 5181

24) (2) 1/16. {see attachment}

Step-by-step explanation:

Ans 23:

s= a+b+c/2

  51 +37+20/2

 =54

area = √s(s-a)(s-b)(s-c)

        = √54 (54-51)(54-37)(54-20)

        =√54(3)(17)(34)      {simplest form}

        = √(3*2*3*3)*(3)*(17)*(17*2)

        = 3*2*3*17

        = 306m²

area needed for flower beds

              =  306/9

              =  34

∴ 34 flower beds are required to occupy the space

Ans 24 (1):

Radius of the base = r = 0.5 m = 0.5 × 100 cm = 50 cm

Height= h = 1.4 m = 1.4 × 100 cm = 140 cm

Surface area to be tin-coated = 2( 2πrh + πr²)

= 2[(2 × 3.14 × 50 × 140) + (3.14 × 50 x 50)]

Cost of tin-coating at the rate of Rs. 50 per 1000 cm2 = Rs 1000

Total cost = 50/1000 × 103620

= Rs 5181

Hope it clears your query.

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