Hi Guys....
Please solve this question...
Find the magnitude of A, if
2sinA cosA - cos A - 2sin A +1=0
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Answer:
2sinAcosA-cosA-2sinA+1=0
cosA(2sinA-1)-1(2sinA-1)=0
(cosA-1)(2sinA-1)=0
cosA-1=0 or 2sinA-1=0
cosA=1 or 2sinA=1
A=0 or sinA=1/2
A=0° or A=30°
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