Question

hi guys pls tell me this answer tomorrow is my exam so pls tell as fast as you can thanks alot . A merchant has 120 litres of oil of one kind, 180 litres of another
kind and 240 litres of a third kind. He wants to sell the oil by filling
the three kinds of oil in tins of equal capacity. What should be the
greatest capacity of such a tin?
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Answer 1

Step-by-step explanation:

Quantity of oil A = 120 liters Quantity of oil B = 180liters Quantity of oil C = 240liters We want to fill oils A, B and C in tins of the same capacity ∴ The greatest capacity of the tin chat can hold oil. A, B and C = HCF of 120, 180 and 240 By fundamental theorem of arithmetic 120 = 23 × 3 × 5 180 = 22 × 32 × 5 240 = 24 × 3 × 5 HCF = 22 × 3 × 5 = 4 × 3 × 5 = 60 litres The greatest capacity of tin = 60 litres.

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