Question

hi guys
plz ANSWER the numerical given above
From ncert class 9 sci
Best answer will be MARKED as Brainlist
UNNECESSARY ANSWER will be DELETED ​

Answer 1

(mass), m  = 1kg

u, (initial velocity) = 20m/s. v = 0m/s.

s (distance travelled) = 50m

Using third equation of motion,

v² = u²+ 2as

$0^{2} = (20)^{2} + 2(a)(50)$

$0 = 400 + 100a$

-400 = 100a

-4 = a

acceleration, $a = 4ms^{-2}$  (retardation or negative acceleration)

force, F = m × a

F = 1 × (-4) = -4N. (negative sign indicates the opposing force which is Friction)

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Answer 2

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