Question

hi guys plz help me...........​

Answer 1

Given that : 27x³ + y³ + z³ – 9xyz

=> (3x)³ + y³ + z³ – 3.(3x)yz

As we know that :

a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

Now, on putting a = 3x, b = y and c = z in the given formula :

(3x+y+z)[(3x)²+y²+z²-3xy-yz-3xz)

=> (3x+y+z)(9x²+y²+z²-3xy-yz-3xz)

I hope it will be helpful for you ✌️✌️

Plzz follow me ☺️☺️

Answer 2

Step-by-step explanation:

hope it helps!!!!

plzzz say thnx !!!!!!