Question

Hi guys plz help me
Find the sum to n terms of the series
(i) 0.4 +0.44 +0.444 + ... to n terms​

Answer 1

Answer:

4(0.1+0.11+0.111+.....to n terms)

4/9{0.9+0.99+0.999....to n terms}

4/9{(1-0.1)+(1-0.01).(1-0.001)+... To n terms}

4/9{n-[1/10+1/100+1/1000+...to n terms]}

4/9{n - a(1-r^n)/1-r}

4/9{ n - 1/10[1 - (1/10)^n] ÷ 1 - 1/10}

4/9{n - 1/9(1-1/10^n)}

4n/9 - 4/81 [1-(1/10)^n]

Please mark brainliest

Answer 2

4/9{n-10/9 (1-1/10n)}

Hope it's help you dear friend