Question

hi guys plz prove that ax2 + bx+ c = 0 if it has two roots ....... i want full solution...​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Solution:

Given quadratic equation

ax²+bx+c=0

=> ax² + bx = -c

Divide each term by a , we get

=> x² + (bx/a) = (-c/a)

=> x² + 2*x*(b/2a) = -c/a

=> x²+2*x*(b/2a)+(b/2a)² = -c/a + (b/2a)²

=> ( x+b/2a)² = -c/a+b²/4a²

=> (x+b/2a)² = (-4ac+b²)/4a²

=> x+b/2a = ±√[(-4ac+b²)/4a²]

=> x = -b/2a±√(b²-4ac)/2a

=> x = [-b±√(b²-4ac)]/2a

Therefore,

The two roots of given Quadratic equation are

x = [-b+√(b²-4ac)]/2a

Or

x = [-b-√(b²-4ac)]/2a

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