Hi guys....
Q. Set up an equation in the following cases :
i. In an isosceles triangle, the vertex angle is twice either base angle.( Let the base angles be in degrees. Remember that the sum of angles of a triangle is 180 degrees )
Want the answer with clear explanation....
Pls answer quickly
For 40 points...
Answers
Answered by
1
The equation will be 2b+b+b = 180° .
Let, base angle be "b".
So, vertex angle= 2b
Sum of angles in a triangle= 180 degrees
There are 2 base angles and 1 vertex angle.
So,
2b+b+b = 180
4b= 180
b=180/4
b=45 degrees.
Therefore,
b=45 degrees
HOPE IT HELPS YOU....
Answered by
0
Answer:
Step-by-step explanation:
Let, base angle be "b".
So, vertex angle= 2b
Sum of angles in a triangle= 180 degrees
There are 2 base angles and 1 vertex angle.
So,
2b+b+b = 180
4b= 180
b=180/4
b=45 degrees.
Therefore,
b=45 degrees
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