Question

hi, guys solve the following one.

Answer 1

determine rs by phythogaras...we get 15

and after that determine pq by pythogaras again we get 12..

so ar(quadrilateral)=ar(triangle spq)+ar(triangle sqr)

=1/2*9*12+(1/2*8*15)
=54+60
=114cm²

Answer 2

Pikachu! Your answer ^^
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In ΔQRS

We are gonna pythagorean theorem to find the side SQ as it is right angle triangle

√SR² - QR²

√17² - 8²

√289 - 64 = √225 = 15 cm

We have to find the area of quadrilateral PQRS which is the sum of the areas of ΔQRS and ΔPQS

Area of ΔQRS = 

$\frac{1}{2} * B * H = \frac{1}{2} * 15 * 8 = 60 cm^{2}$


Now in ΔPQS = 

PQ = √SQ² - SP² = √15² - 9² = √225 - 81 = √144 = 12 cm

Area of ΔPQS = 

$\frac{1}{2} * 9 * 12 = 54 cm^{2}$

Now area of quadrilateral will be = 54 + 60 = 114 cm²
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Pikachu! ^_~