Hi guys
solve this ........
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2x^2+ax-a^2=0
2x^2+2ax-ax-a^2=0
2x(x+a)-a(x+a)=0
(2x-a)(x+a)=0
2x-a=0
2x=a
x=a/2
x+a=0
x=-a
=>x=a/2(or)-a
2x^2+2ax-ax-a^2=0
2x(x+a)-a(x+a)=0
(2x-a)(x+a)=0
2x-a=0
2x=a
x=a/2
x+a=0
x=-a
=>x=a/2(or)-a
PARI1111111:
hope u understood....
yeah
tq u sis
no mention....its my duty...
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