Question

hi guys solve this qsn​

Answer 1

Answer:

c) 45mΩ

Explanation:

• Let the voltage across 300Ω resistor is V1 and 2kΩ resistor is V2

• Breakdown voltage = 10V

• Zener diode regulates the voltage of 2×10³Ω resistor. Hence the voltage across this resistor remains constant, i.e.,V2 = 10V

Applying Kirchoff voltage rule:

25V = V1 + V2

25V = V1 + 10V

V1 = 15V

Current across 300Ω resistor will be:

I = V/R

I = 15/300

I = 0.05 A

Applying Kirchoff current rule:

I = Iz + Ir

0.05 = Iz + Ir

Ir = 0.05 - Iz ------(1)

Current across 2kΩ resistor will be:

Ir = V/R

0.05 - Iz = 10/2×10³

Iz = 5×10^-2 - 5×10^-3

Iz = (50 - 5)×10^-3

Iz = 45×10^-3Ω

Iz = 45mΩ

Current through zener diode Iz = 45mΩ

Answer 2

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