Question

hi guys solve this qsn #wrong answers will be reported @ never give up​

Answer 1

Answer:

not able to read can you retake the pic of this picture

Answer 2

${ \green{ \underline{ \huge{ \mathfrak \red{♡Answer}}}}}$

${ \pink{{{ \mathbb{ = > }}}}}Yes \: ur \: answer \: is \: right... \\ bcz \: we \: knw \: the \: secondary \: transformer \\ supplies \: the \: disired \: ac \: voltage \\ across \: terminals... \\ when \: the \: voltage \: D\: is \: positive \\ the \: diode \: is \: forward \: biased \: and \\ it \: conducts... \\ when \: D\: is \: negative \: the \: diode \: is \\ reverse \: biased \: and \: it \: doesn't \\ conduct...$

${ \pink{{{ \mathbb{ = > }}}}}Therefor \: we \: also \: knw \:that \\ in \: half \: wave \: rectifier \: the \: 1st \\ half \: cycle \: is \: + ve \: and \: conducts \\ ie \: current \: flows \: but \: 2nd \: half \\ cycle \: is \: - ve \: n \: is \: in \: reverse \: biased \\ therfor \: doesnt \: conduct \: ie \: noo \\ current \: flow... \\ and \: 3rd \: half \: cycle \: again \: is \: in \\ + ve \: n \: coducts \: ie \: current \: flows...$

${ \green{{{ \mathbb{therefor \: we \: can \: conclude \: that \: in }}}}} \\ { \green{ { { \mathbb{a \: half \: wave \: rectifier \: current}}}}} \\ { \green{ { { \mathbb{flows \: in \: 1st \: and \: 3 rd \: half \: cycle only...}}}}}$

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${ \red{ \fbox{ \green{ \blue{ \underline{ \mathcal \purple{hope \: this \: helps \: u}}}}}}}$

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