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THE BASE OF AN ISOSCELES TRIANGLE IS 4/5 CM.THE PERIMETER OF THE TRIANGLE IS 4 2/15 CM. WHAT IS THE LENGTH OF EITHER OF THE REMAINING EQUAL SIDES???
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Explanation:
Let each of equal sides of an isosceles triangle = x cm.
The base of an isosceles triangle = 4/3 cm
Perimeter of a triangle = 4 2⁄15 cm
Sum of three sides = 4 2⁄15 cm
Accordding to question :
x + 4/3 + x = (60 + 2)/15
2x = 62/15 - 4/3
2x = (62 - 20)/15
2x = 42/15
x = 42/30
x = 7/5
Each of equal sides of an isosceles triangle = x = 7/5 cm.
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Let each of equal sides of an isosceles triangle = x cm.
The base of an isosceles triangle = 4/3 cm
Perimeter of a triangle = 4 2⁄15 cm
Sum of three sides = 4 2⁄15 cm
By condition,
x + 4/3 + x = (60 + 2)/15
2x = 62/15 - 4/3
2x = (62 - 20)/15
2x = 42/15
x = 42/30
x = 7/5
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