Question

hi guyz!!
please solve!!!​

Answer 1

Given-:

Mass of stone=> 0.1kg

Height => 100m

To find-:

Velocity of particle when it reaches to earth=?

Kinetic energy of particle when it reaches to earth=?

Solution-:

By energy conservation theorem-:

Initial Energy(Potential energy)=> mgh=>0.1×10×100=>100

Final Energy[Kinetic energy] => (1/2)mv² => (1/2)×0.1×v²

By conserving energy means, final energy=initial Energy

=>100=(1/2)×0.1×v²

=> v=√2000

=> v=20√5

Now Kinetic energy=> (1/2)mv²

Kinetic energy=> (1/2)×0.1×2000

Kinetic energy=> 100

So when particle reaches the earth then it will have velocity = 20√5m/sec. and Kinetic energy will be=> 100J

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