hi guyzxz wsssup
plzz solve this question
50 points definitely otherwise report me
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here is the first part of the ques...
main thing is the method to do it...
but be careful while doing calculations...
main thing is the method to do it...
but be careful while doing calculations...
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Dushyant89:
hey how can i attach the pic of second part...
hey its showing i have to answer more questions if i want to message u personally
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From the equation a+b = -1/6, and ab = -1/6
i) a³b+ab³
= ab(a²+b²)
= ab[ (a+b)² -2ab ]
= -1/6 [ (-1/6)² - 2(-1/6) ]
= -1/6(13/36)
= -13/216
ii) a/b + b/a + 2(1/a + 1/b) + 3ab
= (a²+b²)/ab + 2(a+b)/ab + 3ab
= [ (a+b)² - 2ab ]/ab + 2(a+b)/ab + 3ab
= -13/6 - 2 - 1/2
= -14/3
i) a³b+ab³
= ab(a²+b²)
= ab[ (a+b)² -2ab ]
= -1/6 [ (-1/6)² - 2(-1/6) ]
= -1/6(13/36)
= -13/216
ii) a/b + b/a + 2(1/a + 1/b) + 3ab
= (a²+b²)/ab + 2(a+b)/ab + 3ab
= [ (a+b)² - 2ab ]/ab + 2(a+b)/ab + 3ab
= -13/6 - 2 - 1/2
= -14/3
Is it -2/3
yes
It's a calculation mistake
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