Question

Hi, Hellos and Namste

Here are 2 fresh questions for you all :-

Ques 1) If x = 2 and y = - 2, then find value of x - y ^( x - y ).

Ques 2) [ x / x^( 1.5 ) ] = 8x^-1 and x > 0, then x is?

❎ No Spamming ❎

I want full solution, if any confusion then ask in comments.

Have a Great Day Ahead

Answer 1

(1)

Given x = 2 and y = -2.

Now,

= > x - y^(x - y)

= > 2 - (-2)^(2 - (-2))

= > 2 - 2^(2 + 2)

= > 2 -  2^4

= > 2 - 16

= > -14.



(2)

Given Equation is [x/x^1.5)] = (8x)^-1

$= \ \textgreater \ \frac{x}{ x^{1.5} } = 8x^{-1}$

$= \ \textgreater \ x = \frac{8 x^{1.5} }{x}$

On squaring both sides, we get

$= \ \textgreater \ x^2 = ( \frac{ 8x^{1.5} }{x} )^2$

$= \ \textgreater \ x^2 = ( \frac{8^2x^3}{x^2} )$

$= \ \textgreater \ x^2 = 64x$

[tex]= \ \textgreater \ x = 64. [/tex]


Hope this helps!

Answer 2

$\textsf{\green{Given!!}}$

$\textsf{\orange{x=2 and y=-2}}$

$<b><u>NOW,$

$\large\sf\implies\: x\:-y^(x-y)$

$\large\sf\implies\:2-(-2)^(2-(-2))$

$\large\sf\implies\: 2-2^(2+2)$

$\large\sf\implies\:2-2^4$

$\large\sf\implies\:2-\:16$

$\large\bf\implies\:=-14$