Question

hi, help me out, in these questions:

Q1) (a-1)(a+1) = ....... *

SOLUTION:
ï) a^2+1
ïï) a^2-1
ïïï) 2a-1
ïv) None of the above

Q2. Terms having the same variable and the same power for each variable are called Unlike terms .

SOLUTION:
ï) True
ïï) False

Q3. A quadratic Polynomial can be factorised completely . *

SOLUTION:
ï) True
ï) False

Q5. (s-6)(s-3) - (3-s) = *

SOLUTION:
ï) (s-3)(s-7)
ïï) (s-3)(s-6)
ïïï) (3-s)(5-s)
ìv) (3-s)(6-s)

Q6. The factors needed for the middle term splitting of p² - 16p + 39 are *

SOLUTION:
ï) -13,-3
ïï) 13,3
ïïï) 13,-3
ïv) -13,3

Q7. A linear equation is a first degree equation. *

SOLUTION:
ï) T
ïï) F

Q8. If both sides of an equation are divided by a negative number, the equation remains unchanged. *

SOLUTION:
Ï) T
ÏÏ) F

Q9. 0.9a - 2.5 = 0.8a + 1.5 ,find a *

SOLUTION:
Ï) 4
ÏÏ) -4
ÏÏÏ) 5
ÏV) 6

Q10. A value which satisfies an equation is the *

SOLUTION:
ï) Solution of equation
ïï) Root of equation
ïïï) Equation
ïv) Both a and b

Q11. (3a - 0.1)^2 = *

SOLUTION:
ï) 9a^2 - 0.01 - 0.6a
ïï) 9a^2 + 0.01 + 0.6a
ïïï) 9a^2 + 0.01 - 0.6a
ïv) None of these
No irrevelant answers, otherwise reported ❤️​

Answer 1

Answer:

SOLUTION:

ï) a^2+1

ïï) a^2-1

ïïï) 2a-1

ïv) None of the above

Q2. Terms having the same variable and the same power for each variable are called Unlike terms .

SOLUTION:

ï) True

ïï) False

Q3. A quadratic Polynomial can be factorised completely . *

SOLUTION:

ï) True

ï) False

Q5. (s-6)(s-3) - (3-s) = *

SOLUTION:

ï) (s-3)(s-7)

ïï) (s-3)(s-6)

ïïï) (3-s)(5-s)

ìv) (3-s)(6-s)

Q6. The factors needed for the middle term splitting of p² - 16p + 39 are *

SOLUTION:

ï) -13,-3

ïï) 13,3

ïïï) 13,-3

ïv) -13,3

Answer 2

Answer:

equation

ïïï) Equation

ïv) Both a and b

Q11. (3a - 0.1)^2 = *

SOLUTION:

ï) 9a^2 - 0.01 - 0.6a

ïï) 9a^2 + 0.01 + 0.6a