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A share ,a cylindrical and a cone are of the same radius and same height.Find the ratio of their curved surface areas....
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Hey mate!!.
Here's is ur answer _________________
___________________________
The hight of sphere is the diameter.
and the cone and cylinder have hight = 2r.
Then..
CSA of sphere = 4pi(r^2).
CSA of cylinder = 4pi( r^2).
CSA of cone = pi( rl).
where l =
![\sqrt[?]{?} ( r2 + h2) = \sqrt[?]{?}(r2 + (2r)2) = \sqrt[?]{?} (5r2) = r \sqrt[?]{?} 5 \sqrt[?]{?} ( r2 + h2) = \sqrt[?]{?}(r2 + (2r)2) = \sqrt[?]{?} (5r2) = r \sqrt[?]{?} 5](https://tex.z-dn.net/?f=+%5Csqrt%5B%3F%5D%7B%3F%7D+%28+r2+%2B+h2%29+%3D++%5Csqrt%5B%3F%5D%7B%3F%7D%28r2+%2B+%282r%292%29+%3D++%5Csqrt%5B%3F%5D%7B%3F%7D++%285r2%29+%3D+r+%5Csqrt%5B%3F%5D%7B%3F%7D+5)
CSA of cone =
![\pi \sqrt[?]{?} 5r2 \pi \sqrt[?]{?} 5r2](https://tex.z-dn.net/?f=%5Cpi+%5Csqrt%5B%3F%5D%7B%3F%7D+5r2)
now ..
CSA of cylinder, sphere and cone..
4pi(r2) : 2pi (rh): pi(rl).
= 4pi( r2) : 4pi(r2) : pi( r2) root 5.
then.
4: 4: root 5.
Here's is ur answer _________________
___________________________
The hight of sphere is the diameter.
and the cone and cylinder have hight = 2r.
Then..
CSA of sphere = 4pi(r^2).
CSA of cylinder = 4pi( r^2).
CSA of cone = pi( rl).
where l =
CSA of cone =
now ..
CSA of cylinder, sphere and cone..
4pi(r2) : 2pi (rh): pi(rl).
= 4pi( r2) : 4pi(r2) : pi( r2) root 5.
then.
4: 4: root 5.
sathvikaa:
wrong answer
Answered by
0
1:3
hi my dear frnd
ans is 1:3
very fine and what about you
hi my dear frnd
ans is 1:3
very fine and what about you
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