Math, asked by sonikaahlawat210, 9 months ago

Hi huys plz answer this question. I will give you a 5 star rating and thanks and mark ur answer brainliest if u will give a proper and good answer. But only 8f the answer is neat and properly given...

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Answered by Anonymous
7

Answer:

 {a}^{2}  +  {b}^{2}  = 100 \\ and.... \\  \\ ab = 48 \:  \\  \\ so... \\  \\  \\ (a + b) {}^{2}  - 2ab = 100 \\  \\  =  >( a + b) {}^{2}  = 100 - 2 \times 48 \\  \\  \\  =  >( a + b) {}^{2}  = 100 - 96 \\  \\  =  > (a + b) {}^{2}  = 4 \\  \\  =  > a + b =  \sqrt{4}  =  > 2

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Answered by EuphoricEpitome
3

Given :

a² + b² = 100

ab = 48

To find :

Value of a+b

Solution :

We know that,

{\pink{\boxed{(a+b)^2 = a^2 + b^2 + 2 ab }}}

 by \: putting \: the\:values \\ \\ \\ (a+b)^2 = 100+ 2(48) \\ \\ \\ (a+b)^2 = 100+96 \\ \\ \\ (a+b)^2 = 196 \\ \\ \\ (a+b) = \sqrt{196} \\ \\ \\ (a+b) = \sqrt{13 \times 13} \\ \\ \\ {\purple{\boxed { (a+b) = 13}}}

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