Question

Hi I need some help. I need to set up two linear equations with 2 variables. Here's the problem Anna has the Triple age of her son Jaime. In 15 years later the age of anna will be the double of her son. How many years is Anna more than her son?

Answer 1

Answer:

Step-by-step explanation:

Let Anna's age be x and son Jaime's age be y

Age after 15 years will be x+15 and y+15

Given x = 3y ---------------(1)

x+15=2(y+15) ----------------(2)

Substitute x=3y in (2)

3y+15=2y+30

y=15

x=45

Anna's age =45 and son Jaime's age =15

Answer 2

Answer:

30 years

Step-by-step explanation:

let age of Anna be x and age of Jaime be y

x = 3y

=> x-3y = 0.............(1)

x+15 = 2(y+15)

x-2y = 15...........(2)

eqn (1) - eqn (2)

=> y = 15

therefore difference of ages

= x-y

= 3y-y

= 2y

= 30 years

Anna is 30 years more than his son.

hope this helps you