Hi i will mark as brain list
Please tell me answer of this question in easy way but Step-by-step explanation
Answers
Answer:
(9x² + 4y²)(3x + 2y)(3x - 2y)
Step-by-step explanation:
Given Equation is 81x⁴ - 16y⁴
= (9x²)² - (4x²)²
∴ a² - b² = (a + b)(a - b)
= (9x² + 4y²)(9x² - 4y²)
= (9x² + 4y²)[(3x)² - (2y)²]
= (9x² + 4y²)[(3x + 2y)(3x - 2y)]
= (9x² + 4y²)(3x + 2y)(3x - 2y)
Hope it helps!
This is a reasonably straightforward 'difference of squares' problem
What you should do is rewrite this as follows:
81(x^2)^2-16(y^2)^2
If you find it makes it easier, you can then set some arbitrary variable equal to (x^2) and (y^2), say u and v. So the above turns into this:
81u^2-16v^2
Which will factor into
(9u-4v)(9u+4v)
Now put back your x^2 and y^2, and you can see you get another difference of squares (along with a sum of squares), so that would factor into:
(9x^2-4y^2)(9x^2+4y^2) = (3x-2y)(3x+2y)(9x^2+4y^2)
Now if you are working with complex numbers, you can break down the sum of squares further, into this:
(3x+2iy)(3x-2iy)
Where i is the square root of -1.
So the whole result factored as far as possible would look something like this:
(3x+2y)(3x-2y)(3x+2iy)(3x-2iy)