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⭕if the radius of the base of a cylinder is 2.8 cm and its height is 5.5 cm. find its curved surface area and total surface area❓❓ ☺️☺️
Answers
A=2πrh+2πr^2=
2·π·2.8·5.5+2·π·(2.8)^2
≈
146.02123cm²
Answer:
Given :
radius of the cylinder ( r ) = 2.8 cm .
height of the cylinder ( h ) = 5.5 cm .
The curved surface area of a cylinder is given by the formula :
C.S.A = 2 π r h
↪ Curved Surface Area = 2 π r h
⇒ Curved Surface Area = 2 × 22/7 × 2.8 cm × 5.5 cm
⇒ Curved Surface Area = 2 × 22/7 × 28/10 cm × 5.5 cm
⇒ Curved Surface Area = 2 × 22 × 4/10 × 5.5 cm²
⇒ Curved Surface Area = 44 × 4/10 × 55/10 cm²
⇒ Curved Surface Area = 176/10 × 55/10 cm²
⇒ Curved Surface Area = 17.6 × 5.5 cm²
⇒ Curved Surface Area = 96.8 cm² .
The curved surface area of the cylinder is 96.8 cm² .
↪ Total surface area= 2 π r ( r + h )
⇒ Total surface area = 2 π r² + 2 π r h
⇒ Total surface area = 2 π r² + 96.8 cm²
⇒ Total surface area = 2 × 22/7 × ( 2.8 cm )² + 96.8 cm²
⇒ Total surface area = 44/7 × 7.84 cm² + 96.8 cm²
⇒ Total surface area = 44 × 1.12 cm² + 96.8 cm²
⇒ Total surface area = 49.28 cm² + 96.8 cm²
⇒ Total surface area = 146.08 cm²
The total surface area of the cylinder is 146.08 cm² .
Step-by-step explanation:
↪ A cylinder has cross section of a circle .
↪ The solution is made short by adding the curved surface are to the lateral surface area .
↪ The lateral surface area is the area of the curved surface of the cylinder .
↪ The total surface area includes the area of the two circles at each ends .