Question

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Please tell me answer of this question in easy way but Step-by-step explanation


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Answer 1

Answer is attached above.......

Answer 2

Step by Step process :

As you can see that there is right angle triangle ∆OMA

in which OM=11cm.

AM=AB/2

(Because from centre when there is a normal has been made on a chord perpendicularly,it divides the chord in two equal parts.)

AM =120/2=60cm.

so by Pythagoras theorem :

${ ao }^{2} = {om}^{2} + {am}^{2}$

AO^2=60^2+11^2

AO=61cm.

now AO is radius of the circle

and we want to find the length of AD which the diameter of the circle

so AD = 2×radius

AD=2×61 =122cm.

I hope you understand the solution.

Please make this as brainliest answer !