Hi ,
if wave equation Y = a/b+4x² at t= 0
and Y = a/b+ (2x+160)² at t = 2s
Find the direction of propagation and the velocity of wave .
Answers
Answered by
1
Answer:
40m/s towards -ve x-axis.
Explanation:
Substituting in the equation at t = 2s yields the same form of the equation as that at t = 0, so the wave has travelled from x = 0 to x = -80 in 2 seconds.
This implies that the wave is travelling towards the negative x-axis (-x) and its velocity is: 80/2 unit/s = 40 unit/s.
If x is in m, 40 m/s.
Answered by
2
Solution :-
direction ------> - ve (-x)
°•° y = a/b+(kx+ wt)²
y = a/b+ (2x+160)²
at t = 2 sec
•°• y = a/b+ (kx+2w)²
kx= 2x
k = 2
2w = 160
w = 80
v = w/k = 80/2 = 40 m/s Answer ✔
direction ------> - ve (-x)
°•° y = a/b+(kx+ wt)²
y = a/b+ (2x+160)²
at t = 2 sec
•°• y = a/b+ (kx+2w)²
kx= 2x
k = 2
2w = 160
w = 80
v = w/k = 80/2 = 40 m/s Answer ✔
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