Question

hi mates pls can you help me

Answer 1

since the no are odd consecutive
so one no. be x and other be x+2

now according to question

1/x + 1/(x+2)= 12/35
(2x+2 )35 =( x^2 +2x)12
70x + 70 = 24x^2 +24x
24x^2 -47x -70 = 0
plz apply formulae
(-b +-√{b^2-4ac} )/2a

ty

Answer 2

Sure I will help you.

Let the first small odd number be a.

Then the next odd be a+2.

a+1 will be an even number.

Their reciprocal's sum is 12/35

Reciprocal is 1/a and 1/a+2

So basically:

1/a+1/a+2=12/35

Multiply the denominators:

(a+2+a)/a²+2a=12/35

2a+2=12a²+24a/35

70a+70=12a²+24a

=12a²-46a-70=0

=12a²-60a+14a-70=0

12a(a-5)+14(a-5)=0

(12a+14)(a-5)=0

a=5 or a=-14/12

but a is natural so a=5.

a+2=5+2=7

The 2 numbers are 5 and 7

Hope it helps you.