Question

Hi!:)
No Spamming!

In a conductor, 6.25 * 10^16 electrons flow from its end A to B in 2 seconds. Find the current flowing through the conductor. ( e = 1.6 * 10^19 C )

Answer 1

HELLO MATE【◆◆◆◆◆】【●●●●●】----------------------------

☯️☯️No. of electrons = 6.25×10^16

Charge on each electron= 1.6 × 10^-19 C

So total charge Q

= 6.25×10^16 × 1.6 ×10^-19

= 6.25 × 1.6 × 10^-3

= 10 × 10^-3

= 10^-2 C

Time t= 2s

so current I = Q/t

= (10^-2)/2

=1/100×2=1/200

= 0.005 A

= 5× 10^-3 A

= 5 mA✔️✔️

HOPE THIS HELP YOU..☺️☺️