Question

hi phy problem
9th std ICSE​

Answer 1

Given,

Initial Velocity (u) = 10 m/s

Final Velocity (v) = 0 m/s

Time (t) = 20 s

=> v = u + at

=> 0 = 10 + a x 20

=> -10 = 20a

=> -10/20 = a

=> a = -0.5 m/s^2

Hence there is retardation.

Again,

=> v^2 - u^2 = 2aS

=> 0^2 -(10)^2 = 2 x -0.5 x S

=> -100 = -1 x S

=> S = -100/-1

=> S = 100 m

So the Distance transversed = S = 100 m

and

Acceleration = - 0.5 m/s^2