Question

hi please answer me

Answer 1

HEY THERE!!!

Question: 4x²+24x+20

Method Of Solution: Splitting method!!

According to the Question!

=> 4x²+24x+20

Step: Divide the Quadratic Equation by 4.

=> 4x²+24x+20

=> 4(x²+6x+5)

=> 4[x²+5x+x+5]

=> 4[x(x+5)+1(x+5)]

=> 4(x+5)(x+5)

Thanks!☺

Answer 2

Given:

4 x² + 24 x + 20

We have to split 24 x such that we can factorise the expression:

24 x can be broken into 20 x + 4 x

==> 4 x² + 20 x + 4 x + 20

Now take 4 x as common in the first 2 terms and 4 as common in the last 2 terms :

==> 4 x ( x + 5 ) + 4 ( x + 5 )

Now we can write this as :

==> ( 4 x + 4 ) ( x + 5 )

Take 4 common in 4 x  +  4

==> 4 ( x + 1 ) ( x + 5 )

Hence the required answer is :

4 ( x + 1 ) ( x + 5 )

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If we are to find the zeroes of the polynomial:

( x + 5 )( 4 x + 4 ) =0

Either x + 5 =0

==> x = - 5

or 4 x + 4 =0

==> 4 x = -4

==> x = -4 /  4

==> x = -1

The zeroes are -1 or -5 .

Hope it helps you

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