Question

hi please answer me bhai ppease​

Answer 1

$2 {}^{ - x} \times {2}^{10} = {2}^{3x} \times {2}^{ - 2} \\ = > \frac{1}{2 {}^{x} } \times {2}^{10} = {2}^{3x} \times \frac{1}{ {2}^{2} } \\ = > {2}^{10} \times {2}^{2} = {2}^{3x} \times 2 {}^{x} \\ = > {2}^{10 + 2} = 2 {}^{3x + x} \\ = > {2}^{12} = {2}^{4x} \\ bases \: are \: equal \: we \: should \: equal \\ \: the \: powers \\ = > 12 = 4x \\x = \frac{12}{4} = > x = 3 \\ formulas \: used \: .. \\ 1) \: {a}^{ -n } = \frac{1}{ {a}^{n} } \\ 2) {a}^{m} \times {a}^{n} = {a}^{m + n}$

Answer 2

Answer:

Answer is 3

Step-by-step explanation:

$\ \ \ \ \ 2^{-x}\times2^{10} = 2^{3x}\times2^{-2} \\ \implies \frac{2^{-x}}{2^{3x}}=\frac{2^{-2}}{2^{10}}\\ \implies 2^{(-x-3x)}=2^{(-2-10)} \\ \implies 2^{-4x} = 2^{-12}\\ \implies-4x = -12\\ \implies x = \frac{12}{4}\\ \implies x = 3$