Question

Hi please answer this

Answer 1

let p be other root of the quadratic

${x}^{2} - qx + 10 = (x - 5)(x - p) = {x}^{2} - (5 + p)x + 5p$
thus obviously p= 2
thus q= 7

I answered first
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Answer 2

put x = 5 in the equation
then
${5 }^{2} - 5q + 10 = 0$
25+10 = 5q
35 = 5q
q =7
since this question has highest power equal to 2 so the order of equation is 2