Question

Hi please answer this fast
A gas with a volume of 4 at a pressure of 207 KPa is allowed to expand.
The increase is 200 % of the original volume. If the temperature is constant,
what is the new pressure of the gas?

Answer 1

Answer:

69KPa

Explanation:

Given:

Initially

V1 = 4 litre

P1 = 207 Kpa

After expansion

V2 = increase:200% of the original volume

     = V1 + 200% V1

     =4+ (200/100 x 4)

     =4+8

     =12 litre

P2 = ?

Formula:

P1V1=P2V2

(substituting the values)

207 x 4 = 12 x P2

828 = 12 x P2

P2 = 828/12

P2 = 69 Kpa

Hope it helps