Math, asked by Anonymous, 10 months ago

hi......, please answer this question
answer both of them​

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Answers

Answered by sonali3971
3
i hope its help you.......
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Anonymous: question me cosec diya tha
Anonymous: app sec kar dhi
Anonymous: 2nd question also
sonali3971: aap is concept pe banai ban jayega
Answered by yuvraj765
6
HOPE IT WILL HELP UU...


2)

b*2 -4ac

=(2ac+2bd)^2-4(a^2+b^2)(c^2+d^2)
=4a^2c^2+4b^2d^2-4a^2c^2-4a^2d^2-4b^2c^2-4b^2d^2

= -4a^2d^2 - 4b^2c^2
= -4(a^2d^2+b^2c^2)

-4(a^2d^2+b^2c^2)<0

therefore b^2-4ac has no real roots.....
PLS MARK IT AS BRAINLIEST.... ;-D

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yuvraj765: pls mark my ans as brainliest *_*
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