hi,☺
please answer this question with explanation!!
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ABCD is a parallelogram.
AE=AD
then ∆AED is isoceles.
<ADE=180-<DCF=180-115=65°.
<AED=<ADE........AE=AD
<FEC=180-(<EFC+<ECF)=180-(80+65)=180-145=35°
<AEG=<AED-<FEC=65°-35°=30°
AE=AD
then ∆AED is isoceles.
<ADE=180-<DCF=180-115=65°.
<AED=<ADE........AE=AD
<FEC=180-(<EFC+<ECF)=180-(80+65)=180-145=35°
<AEG=<AED-<FEC=65°-35°=30°
Anonymous:
your answer does not match with any option !!!
hey ithink there maybe mistake in question or option
nope
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