Question

Hi please help me the problem is The area of a rhombus is 40 in. If one diagonal of the rhombus is 8 in, what is the length of the other diagonal? Thank you so much!

Answer 1

Answer :

Given :

Area of the rhombus = 40m²

One diagonal of rhombus= 8m

The other Diagonal = ?

We know that the are of rhombus = d1d2/ 2

According to the problem,

8 × x / 2 = 40

8x = 40 × 2

8x = 80

x = 80/8

x = 10

Value of x = 10

Therefore, the length of other Diagonal is 10m.

Answer 2

SOLUTION :

 

The area of a rhombus = 40 inches (given)

One of the diagonal of it is 8 inches (given)

 

To be found :

The other diagonal of the rhombus

   

As we know that,

 

 

$\bf Area \:\:of \:\:rhombus = \frac{1}{2}\times diagonal \:1\times diagonal\: 2$

 

So,

⇒ $\bf 40 = \frac{1}{2}\times diagonal \:1\times diagonal\: 2$

 

⇒ $\bf 40 = \frac{1}{2}\times 8\times diagonal\: 2$

 

⇒ $\bf 40 = 4\times diagonal\: 2$

 

⇒ $\bf \frac{40}{4} = diagonal\: 2$

 

∴ diagonal 2 = 10 inches

 

Hence,

The length of the other diagonal is 10 inches.