Question

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Answer 1

the question is blurry a clear picture of the question will help u get better results

Answer 2

The value of x is determined to be -6.

Step-by-step explanation:

The given equation is

$\frac{2}{3}(3x-2) = \frac{4}{5}(2x-3)-\frac{4}{3}$

We can solve the above equation as follows:

1. Taking LCM on the right-hand side

$\frac{2}{3}(3x-2) = \frac{3\times4(2x-3)-5\times 4}{15}$

2. Solving the terms on the right-hand side

$\frac{2}{3}(3x-2) = \frac{12(2x-3)-20}{15}$

3. Opening the brackets on the right-hand side

$\frac{2}{3}(3x-2) = \frac{24x-36-20}{15}$

$\frac{2}{3}(3x-2) = \frac{24x-56}{15}$

4. Carrying out cross multiplication

$15\times2(3x-2) = 3(24x-56)$

5. Multiplying and opening the brackets

$30(3x-2) = 3(24x-56)$

$10(3x-2) = (24x-56)$

$30 x-20 = 24x-56$

6. Taking variable x terms on the left-hand side and numbers on the right-hand side.

$30x-24x = 20-56$

7. Solving to get the value of x

$6x = -36$

$x =\frac{-36}{6}$

$x =-6$