Hi please help me with this question please if you know only one of them thennit is fine too
Answers
Step-by-step explanation:
1) Solution :-
Given that -3 ≤ x ≤ 7
The possible values of x = -3,-2,-1,0,1,2,3,4,5,6,7
and
4 ≤ y ≤ 10
The possible values of y = 4,5,6,7,8,9,10
Now,
a )
The smallest possible value of x-y
=> The least value of x - The greatest value of y
=> -3-10
=> -13
b)
The largest possible value of x/y
=> The greatest value of x / The least value of y
=> 7/4
c)
The largest possible value of x²-y²
=> (Largest value of x)² - ( Least value of y)²
=> 7²-(4)²
=> 49-16
=>33
d)
The smallest possible value of x³+y³
=> (The smallest value of x)³+(The greatest value of y)³
=> (-3)³+(4)³
=> -27+64
=> -37
2)
Given that 27-2x ≤ 8
On Subtracting 27 from both sides then
=> 27-27-2x ≤ 8-27
=> -2x ≤ -19
=> 2x ≥ 19
=> x ≥ 19/2
=> x ≥ 9.5
a) The least possible value of x = 9.5
b) The least possible integer value of x = 10
3)
Given that
5x > 69-2x
On adding 2x both sides then
=> 5x + 2x > 69-2x+2x
=> 7x > 69
On dividing by 7 then
=> (7x/7) > (69/7)
=> x > 69/7
=> x > 9.85...
The possible values of x = 10 , 11 ,12...
and
27 - 2x ≥ 4
On subtracting 27 from both sides
=> 27-27 -2x ≥ 4-27
=> -2x ≥ -23
=> 2x ≤ 23
=> x ≤23/2
=> x ≤ 11.5
The possible integer values of x = 12,13,...