Math, asked by dwijakishore, 1 month ago

Hi!

Please solve for 5/sin x 3/sin y - 3 cot y

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Answers

Answered by malaytrivedi12345
7

Answer:

12.75

Step-by-step explanation:

AD²=AC²-DC²

AD²=13²-5²

AD²=169-25

AD²=144

AD=√144

AD= 12

BD=BC-CD

BD=21-5

BD=15

AB²=AD²+BD²

AB²=12²+16²

AB²=144+256

AB²=400

AB=√400

AB=20

Now,

Sin(x)=5/13

Sin(y)=12/20

Cot(y)=21/12

Now,

5/sin(x)+3/Sin(y)-3Cot(y)

(5×13/5)+(3×20/12)-(3×21/12)

13+5-21/4

18-21/4

Taking LCM,

72-21/4

51/4

12.75

Please mark me brainliest

Answered by imran749
9

Answer:

14

Step-by-step explanation:

sinx=5/13

siny=12/20=3/5

coty=16/12=4/3

NOW SUBSTITUTE THE VALUE ;

5/5/13 + 3/3/5 - 3*4/3

now, 5*13/5 + 3*5/3 - 4 (3 cancelled out )

* cancel the numbers *

u will get 13+5-4

ANS=14

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