Hi!
Please solve for 5/sin x 3/sin y - 3 cot y
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Answered by
7
Answer:
12.75
Step-by-step explanation:
AD²=AC²-DC²
AD²=13²-5²
AD²=169-25
AD²=144
AD=√144
AD= 12
BD=BC-CD
BD=21-5
BD=15
AB²=AD²+BD²
AB²=12²+16²
AB²=144+256
AB²=400
AB=√400
AB=20
Now,
Sin(x)=5/13
Sin(y)=12/20
Cot(y)=21/12
Now,
5/sin(x)+3/Sin(y)-3Cot(y)
(5×13/5)+(3×20/12)-(3×21/12)
13+5-21/4
18-21/4
Taking LCM,
72-21/4
51/4
12.75
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Answered by
9
Answer:
14
Step-by-step explanation:
sinx=5/13
siny=12/20=3/5
coty=16/12=4/3
NOW SUBSTITUTE THE VALUE ;
5/5/13 + 3/3/5 - 3*4/3
now, 5*13/5 + 3*5/3 - 4 (3 cancelled out )
* cancel the numbers *
u will get 13+5-4
ANS=14
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