Question

hi please solve this ↑​

Answer 1

Answer:

here's ur answer dear!

Step-by-step explanation:

_ first, we know that perimeter of square = 4a

- so, 4a = 44cm

- a = 44/4 = 11

-11*11 = 121cm sq.(area of square)

_now we have to find the perimeter of rectangle that = 2(l+b)

- 2(l+5cm) = 44cm

- l+5 = 22cm              (44/2 = 22)

- l = 22-5

- l = 17cm

- square of rectangle = L*B

- 17*5 = 85cm sq.

_ now, the difference between their areas = 121 - 85 = 36cm sq.

Hence, the area of square is greater than the area of rectangle by 36cm sq.

Hope this will help u !

Answer 2

first, we know that perimeter of square=4a

- so, 4a = 44cm

- a = 44/4 = 11

-11*11 = 121cm sq.(area of square)

_now we have to find the perimeter of rectangle that = 2(l+b)

- 2(l+5cm) = 44cm

- l+5 = 22cm              (44/2 = 22)

- l = 22-5

- l = 17cm

- square of rectangle = L*B

- 17*5 = 85cm sq.

_ now, the difference between their areas = 121 - 85 = 36cm sq.

Hence, the area of square is greater than the area of rectangle by 36cm sq.