Question

Hi pls answer this question..17th one​

Answer 1

the answer is less than zero it means Roots are not real

Answer 2

Step-by-step explanation:

Given Quadratic Equation is (a² + b²)x² + 2(ac + bd)x + c² + d² = 0.

On comparing with ax² + bx + c = 0, we get

a = (a² + b²), b = 2(ac + bd), c = c² + d².

Now,

D = b² - 4ac

  = [2(ac + bd)]² - 4(a² + b²)(c² + d²)

 = 4(a²c² + b²d² + 2acbd) - 4(a²c² + a²d² + b²c² + b²d²)

 = 4(a²c² + b²d²+ 2acbd - a²c² - a²d² - b²d² - b²d²)

 = 4[2acbd - a²d² - b²c²]

 = -4[a²d² + b²c² - 2acbd]

 = -4[ad - bc]²

∴ D < 0

Given that ad ≠ bc and (ad - bc)² > 0

Therefore, the given equation has no real roots.

Hope it helps!