hi pls find the value of y
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Answered by
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here,
in ∆PQR
PQR=90°
PRQ+PRS=180°
PRQ=180°-120°
PRQ=60°
So,
PQR+PRQ+RPQ=180°
90°+60°+y=180°
y=180°-150°
y=30°
in ∆PQR
PQR=90°
PRQ+PRS=180°
PRQ=180°-120°
PRQ=60°
So,
PQR+PRQ+RPQ=180°
90°+60°+y=180°
y=180°-150°
y=30°
Answered by
0
angle PRQ =180-120 =60
Then y = 180 -90 -60 =30
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