Hi . Pls solve the above sum. No spamming. Thank you.
Answers
Step-by-step explanation:
(i) Molar mass of water (H
2
O)
Atomic mass of H=1
Atomic mass of O=16
H
2
O=2×H+1×O
Molar mass of water=2×1+16=18g/mol
(ii) Molar mass of carbon dioxide (CO
2
)
Atomic mass of C=12
Atomic mass of O=16
CO
2
=1×C+2×O
Molar mass of CO
2
=12+2×16=44g/mol
(iii) Molar mass of methane (CH
4
)
Atomic mass of C=12
Atomic mass of H=1
CH
4
=1×C+4×H
Molar mass of methane=12+4×1=16g/mol
Answer:
Step-by-step explanation:
According to the data given the question, the reaction taking placebwill be combustion of methane
CH,+2O, → CO₂ + 2H₂O
Molecular weight of CH4 = 16 g No of moles of CH4 in 16 g is
n =
given weight
molecular weight
16
16
1
Molecular weight of O₂ = 32 g
No of moles of O₂ in 64 g is
n = given weight molecular weight 64 32
2
According to the reaction 1 mole of CH4 and 2 moles of O₂ gives 1 mole of CO2
Weight of 1 mole of CO₂ = 1(C) + 2(0)
= 12+32 = 44 g
Final answer:
The mass of CO₂ formed is 44 g [Option(a)]