Question

hi plz ans fst these questions ​

Answer 1

Answer:

Given :

3 Angle related questions are given .

1st question

We know that total angle around a straight line is 180°.

$\therefore \: 20x + 7x + 9x = 180$

$= > 36x = 180$

$= > x = 5$

So the respective angles are :

$1. \: 20x = 100 \degree \\ 2. \: 9x = 45 \degree \\ 3. \: 7x = 35 \degree$

2nd Question

First find the angles inside the triangle

So the angles inside the triangle comes as :

• 180° - x
• 180° - 110° = 70°
• 180° - 160° = 20°

Now sum of angles of a triangle is 180°

Therefore :

∴ (180 - x) + 70 + 20 = 180

=> x = 90°

3rd Question :

Sum of angles between 2 parallel lines cut by a transverse is 180°

∴ x + 38° + 2x + 38° = 180°

=> 3x + 76° = 180°

=> 3x = 104°

=> x = (104/3)°

=> x = 34.6 °

Answer 2

$\huge {\boxed {\boxed {\mathfrak {\pink {Solution:}}}}}$

$\underline{\bold {In\:First\:Question:}}$

First question showing that the rays are dividing the straight angle in three parts.

Sum of all angles of triangle is 180°.

$\implies 9x + 20x + 7x = 180 \\\\ \implies 36x = 180 \\\\ \implies x = \frac{180}{36} \\\\ \implies x = 5$

Angles are :

• $(9x)^{\circ}=(9\times 5)^{\circ}=45^{\circ}$
• $(20x)^{\circ}=(20\times 5)^{\circ}=100^{\circ}$
• $(7x)^{\circ}=(7\times 5)^{\circ}=35^{\circ}$

$\underline{\bold {In\:Second\:Question:}}$

In second question we first find all angles of triangle to find value of x.

Angle will be

• ${(180-110)}^{\circ}=70^{\circ}$
• ${(180-160)}^{\circ}=20^{\circ}$
• ${(180-x)}^{\circ}$

$\implies 70+20+(180-x)=180\\\\ \implies 70+20+180-x=180\\\\ \implies 270-x=180\\\\ \implies -x=180-270\\\\ \implies -x=-90\\\\ \implies x=90$

Value of x = 90°

$\underline{\bold {In\:Third\:Question:}}$

In third question we know that sum of consecutive interior angle is 180°.

$\implies (x+38)+(2x+38)=180\\\\ \implies x+38+2x+38=180\\\\ \implies 3x+76=180\\\\ \implies 3x=180-76\\\\ \implies 3x=104\\\\ \implies x= \frac{104}{3}\\\\ \implies x=34.7$

Value of x is 34.7°.